C Program To Find Armstrong Number Using Do While Loop

Armstrong Number In Java

Given a number x, determine whether the given number is Armstrong number or not. A positive integer of n digits is called an Armstrong number of order n (order is number of digits) if. = pow(a,n) + pow(b,n) + pow(c,n) + pow(d,n) +.Example:Input: 153Output: Yes153 is an Armstrong number.1.1.1 + 5.5.5 + 3.3.3 = 153Input: 120Output: No120 is not a Armstrong number.1.1.1 + 2.2.2 + 0.0.0 = 9Input: 1253Output: No1253 is not a Armstrong Number1.1.1.1 + 2.2.2.2 + 5.5.5.5 + 3.3.3.3 = 723Input: 1634Output: Yes1.1.1.1 + 6.6.6.6 + 3.3.3.3 + 4.4.4.4 = 1634.